[C Programming #1] Print 1 to 100 without using loops

How to print 1 to 100 numbers without using loops concepts (for/while/do-while) ?
This is a tricky question. Think Think Think.
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Hint: We can use the concept of static variables to do this task.
Think
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Here is the program, which solves the problem.

1. #include<stdio.h>
2. 
   
3. int main()
4. {
5.   static int i = 0;
6. 
   
7. printf("%d\n", i++);
8. if (i<=100)
9.   main();
10. 
    
11. 
    
12. return 0;
13. }

Output: 1 to 100 numbers printed line by line.

Now, we can made a small change in the program to display numbers from x to y;

Here is the program to do this task.

1. #include<stdio.h>
2. 
   
3. int main()
4. {
5.   static int i = 0, x ,y;
6. 
   
7. if (i == 0) {
8.     printf("Please enter two numbers, x should be <= y\n");
9.   printf("x = ");
10.   scanf("%d", &x);
11.   printf("y = ");
12.     scanf("%d", &y);
13.     if (x > y) {
14.     printf("x should be less than or equal to y.\n");
15.   return 0;
16.     }
17. }
18. 
    
19. printf("%d\n", x+(i++));
20. if ((x+i)<=y)
21.   main();
22. 
    
23. return 0;
24. }

Output: Numbers are displayed from X to Y line bye line:

Example output:

Please enter two numbers, x should be <= y

x = 12

y = 17

12

13

14

15

16

17

Example output_2:

Please enter two numbers, x should be <= y
x = 12
y = 6
x should be less than or equal to y.